The Schmitt trigger input is the whole reason for using that gate (an inverter in this case). A standard gate won't have the desired behavior. Its purpose is to take a slowly rising or falling voltage (like what's on a capacitor that's charging or discharging), and ignore noise on the line and suddenly flip the output when it reaches the right threshold. The threshold for going the other direction will be different. If you don't have any Schmitt-trigger gates in your personal stock and don't want to order and wait for one to arrive, you can make one by adding positive feedback with resistors. I show this kind of think in the last diagram at the bottom of http://6502.org/users/garth/projects.php?project=7, but you won't need the open-collector transistor at the output like I needed there to work with the other RST\ sources in the C64. That transistor inverts the signal again; so the rest of your circuit before that would be done in the opposite polarity.

No; if I understand you correctly, you're talking about the same circuit. After the power is up and stable, and the oscillator is stabilized, the reset circuit brings the RST\ line up with a single, fast rising edge, and the processor reads address $FFFC and $FFFD to get the address of where your reset routine in your ROM starts.

The reset circuits in the 6502 primer also work on power-up, not just pushing the button. It gives the reset pulse either way.

but i also found this online where someone implements a different Reset circuit to the Primer.

That one is also in the 6502 primer's reset page, at the bottom.

Yes, they're very slight variations on the same circuit. The diode is to discharge the 10uF capacitor when the power goes down, to make sure you really are starting fresh when it comes up. (The diode used for the same function in the second circuit from the top, which I use, is just the one that's built into the CMOS gate for input protection. The time constant of the capacitor and the 5.6K resistor is only about 25ms.)

now i need to make a footprint for the RAM, since that's the only component i had to make myself and didn't find a symbol/footprint for online.
can't i just copy a standard 28 pin DIP footprint from something else?

There are JDEC standard pinouts for 8-bit wide static ROM (and perhaps RAM as well), and most 24-pin ROMs and RAMs are going to be pretty darn close to the standard. So yeah, you can just copy and tweak. Just confirm everything carefully with the data sheet.

the pinout is not the problem, i already have the symbol (as it can seen on the picture), just not the footprint for the PCB.

Oh, I was talking about footprint: pinouts are footprint, not schematic symbol, to my mind.

I thought about mentioning that the physical dimenions are also standardized by JEDEC, but got lazy and didn't because I figured "DIP is DIP: just copy any existing DIP footprint with the right number of pins and tweak the pinout."

There are JEDEC standard pinouts for 8-bit wide static ROM...

Static ROM? What's that? :D

..."speaking of which i also need a power-up reset circuit" i meant "speaking of reset circuits i also need an additional circuit that brings the reset line low automatically on power up".