Name mux ;
PartNo 00 ;
Date 11/04/2011 ;
Revision 01 ;
Designer Engineer ;
Company University of Tulsa ;
Assembly None ;
Location ;
Device V2500C ;

/* *************** INPUT PINS *********************/
PIN 1=clk ; /* */
PIN 3=x ; /* */
PIN 4=r1 ; /* */
PIN 5=r2 ; /* */
PIN 6=r3 ; /* */
PIN 7=r4 ; /* */

/* *************** OUTPUT PINS *********************/
PIN 9=z ; /* */
PIN 12=q0 ; /* */
PIN 13=q1 ; /* */
PIN 14=q2 ; /* */
PIN 15=q3 ; /* */
PIN 16=q4 ; /* */
PIN 24=q5 ; /* */
PIN 25=q6 ; /* */
PIN 26=q7 ; /* */



/*mux*/
z=!q6&!q7&r1 # !q6&q7&r2 # q6&!q7&r3 # q6&q7&r4;

/*shift Register */
q0.d=x;
q1.d=q0;
q2.d=q1;
q3.d=q2;
q4.d=q3;
q5.d=q4;
q6.d=q5;
q7.d=q6;

on my program when i change q6 and q7 i only get the vlaues of R1 on my out put Z, can any one please help me with it ????

_________________
juda

I have not used that device, but have used WinCUPL.

So, if I read this right, serial data is being shifted in on the x input using the clk input as the shift clock. Bits move from Q0 to Q7.

The z output is Q6 AND'ed with Q7, using R1 thru R4 to select all combinations of inverted/non-inverted Q6's and Q7's.

Only one of R1 thru R4 should be held high at any given time.



So, in order to test this, you need to clock data into x to fill Q6 and Q7. (8 clocks total)

Then, stop clocking and sequentially set R1 thru R4 high and read the results on z.

Here's one example:

With Q6=0 and Q7=1, you should see this:
R1 z=0
R2 z=1
R3 z=0
R4 z=0

Does this help?

Is this what you are doing, or are you doing it differently?

Adding some whitespace here and there helps old eyes like mine read your code, e.g.:

It may be necessary to parenthesize expressions, e.g.:

You should check WinCUPL's evaluation precedence rules to make sure the compiler is seeing your logic the way you want it.

_________________
x86?  We ain't got no x86.  We don't NEED no stinking x86!

thanks

_________________
juda